Method of Multiplication (B)

In our previous blog we known about vedic method of multiplication  . In this blog we will study about vedic method of multiplication I another way .

NOTE -: when will We see the examples below we see that each number multiply with the digits of another number at one time .
 NOTE -: if we acquire this method we will solve multiplication of any two numbers in few seconds .

Let an example -:  solve 79 × 13 .

Solution -:   79 × 13  = 1027
                   
              7×1 = 7  | {(7×3) + (9×1)} | 9× 3=27
                             | = 30                    |
Now we find the required number from these three numbers {7,30,27}  , let see below
         (a) 7 + 3 = 10 | (b) 30+ 2 = 2.| (c)  7

    In (a) -:
 { 3 from tenth digit of 32 }

In (b) -:
 { we add 2 from tenth digit of 27 }

In (c) -:
{unit digit of 27 }

Now the required number is -: 1027 Answer .

Example (2) -:  solve 79 × 326 .

Solution -:  79 × 326 = 25754
7 × 3 | {(7 × 2) + (9 × 3)| {(7 × 6) + (9 × 2)|9×6
= 21 |           = 41.          |      = 60         |= 54

Now we get the required number from these four numbers { 27,41,72,54}  , let see below
   
(A)  21 + 4| (B) 41 + 6| (c) 60 +5 |(d) 4

   = 25        | = 7.           | = 5.         | 4

So Answer will be -: 25754

Example (3) -: Evaluate 325768 × 289 .

Solution -:  325768 × 289 = 94146952.

(A) 9×8 = 72
(B) (8×8)+(9×6) = 118
(C) (2×8)+(8×6)+(9×7) = 127
(D) (2×6)+(8×7)+(9×5) = 113
(E) (2×7)+(8×5)+(2×9) = 72
(F)  (2×5)+(8×2)+(9×3)= 53
(G) (2×2)+(8×3) = 28
(H) 2×3 = 6

OR

2×3| {(8×3)+(2×2)}|{(9×3)+(8×2)+(2×5)}|
(H).         (G).                       (F)
{(9×2)+(8×5)+(2×7)}|{(9×5)+(8×7)+(2×6)}
               (E).                          (D)
{(9×7)+(8×6)+(2×8)}|{(9×6)+(8×8)}|9×8|
          (C).                            (B).              (A)

Now we find the required number from these number (72,118,127,113,72,53,28,6) -

From :
(A)    (2)    unit digit from 72
(B) 118+7 = 125  (5) ,  unit digit from 125
 (C) 127+12 = 139 (9) , unit digit from 139
(D) 113+13 = 126 (6) , unit digit from 126
(E) 72+12 = 84 (4) , unit digit from 84
(F) 53+8 = 61 (1) , unit digit from 61
(G)28 + 6 = 34 (4) , unit digit from 34
(H) 6+3= 9

So the required answer will be 94146952

Note -: we write the digit from bottom to top , like from H to A in above question.